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If the ratio of lengths, radii and young’s modulus of steel and brass wires in the figure are a, b and c respectively, then the ratio of increase in their lengths would be

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$\frac{2 a^{2} c}{b}$

$\frac{3 a}{2 b^{2} c}$

$\frac{2 a c}{b^{2}}$

$\frac{3 c}{2 a b^{2}}$

answer is B.

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Detailed Solution

$e = \frac{F L}{A Y}$ ; $\frac{e_{1}}{e_{2}} = \frac{F_{1}}{F_{2}} \times \frac{l_{1}}{l_{2}} \times {(\frac{r_{2}}{r_{1}})}^{2} \times \frac{Y_{2}}{Y_{1}}$

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