Q.

If the ratio of the roots of x2+bx+c=0 and x2+qx+r=0  are the same, then

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a

r2c=qb2

b

r2b=qc2

c

rb2=cq2

d

rc2=bq2

answer is C.

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Detailed Solution

α,βarerootsofx2+bx+c=0thenα+β=b,  αβ=cLetγ,δarerootsofx2+qx+r=0γ+δ=q,  γδ=rGivenαβ=γδα+βαβ=γ+δγδ(α+β)2(αβ)2=(γ+δ)2(γδ)2(α+β)2(α+β)24αβ=(γ+δ)2(γ+δ)24γδb2b24c=q2q24rb2q24b2r=q2b24q2cb2r=q2c

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