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Q.

If the ratio of the roots of x2+bx+c=0 and x2+qx+r=0 are same, then 

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a

r2c=qb2

b

rb2=cq2

c

r2b=qc2

d

rc2=bq2

answer is C.

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Detailed Solution

αβ=γδ⇒α+βα−β=γ+δγ−δ

⇒−bb2−4c=−qq2−4r

⇒b2(q2−4r)=q2(b2−4c)

⇒b2r=q2c

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