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If the reaction sequence given below is carried out with 5 moles of n-heptane, the amount (in g) of the product [G] formed is _____.
The yields of [A] to [G] are given in parentheses.
Compound [B]has the highest dipole moment among the three compounds that [A] can produce.
[Given: Atomic mass of H = 1, C = 12, N = 14, O = 16, Br = 80]

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answer is 100.5.

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Detailed Solution

$w_{G} = 1 \times 0.5 \times 0.5 \times 1 \times 0.5 \times 1 \times 0.8 \times 5 \times 201 = 100.5 g$

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