If the reading of the ideal ammeter connected in the given circuit is n(1320) ampere, find the value of n. Assume that the cells have negligible internal resistance

I=I1+I2+I3+I4=810−28+24−62 32−10+20−12040=−7840Amp

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If the reading of the ideal ammeter connected in the given circuit is $n (\frac{13}{20})$ ampere, find the value of n. Assume that the cells have negligible internal resistance

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answer is 3.

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$I = I_{1} + I_{2} + I_{3} + I_{4} = \frac{8}{10} - \frac{2}{8} + \frac{2}{4} - \frac{6}{2} \frac{32 - 10 + 20 - 120}{40} = \frac{- 78}{40} A m p$

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