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If the refractive index of diamond is $2.42$ , then the speed of light in diamond is?

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\frac{c}{2.42} m / \sec

2.42 c m / \sec

\frac{2 c}{2.42} m / \sec

\frac{3 c}{2.42} m / \sec

answer is A.

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Detailed Solution

If the refractive index of diamond is

2.42

, then speed of light in diamond is

\frac{c}{2.42} m / \sec

.
We know that,

v = \frac{c}{refractive index}

Given that, Refractive index of diamond is

2.42

and speed of light

= c

Using the formula,

v = \frac{c}{2.42} m / \sec

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