If the resistance of a conductor is 5Ω at 500C, and 7Ω at 1000C, then the mean temperature coefficient of resistance of the material is

Using RT2 =RT1 1+ αT2−T2⇒R100 =R50 1+α 100−50⇒ 7=5 1+α ×50 ⇒α = 7−5250 = 0.008/0C

If the resistance of a conductor is 5Ω at 500C, and 7Ω at 1000C, then the mean temperature coefficient of resistance of the material is

Using RT2 =RT1 1+ αT2−T2⇒R100 =R50 1+α 100−50⇒ 7=5 1+α ×50 ⇒α = 7−5250 = 0.008/0C

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If the resistance of a conductor is $5 Ω$ at 50⁰C, and $7 Ω$ at 100⁰C, then the mean temperature coefficient of resistance of the material is

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0.008/⁰C

0.001/⁰C

0.006/⁰C

0.004/⁰C

answer is A.

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$\begin{array}{l} U \sin g R_{T_{2}} = R_{T_{1}} [1 + α (T_{2} - T_{2})] \\ \Rightarrow R_{100} = R_{50} [1 + α (100 - 50)] \\ \Rightarrow 7 = 5 [1 + (α \times 50)] \Rightarrow α = \frac{(7 - 5)}{250} = 0.008 /^{0} C \end{array}$

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If the resistance of a conductor is 5Ω at 500C, and 7Ω at 1000C, then the mean temperature coefficient of resistance of the material is

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If the resistance of a conductor is $5 Ω$ at 50⁰C, and $7 Ω$ at 100⁰C, then the mean temperature coefficient of resistance of the material is