Q.

If the Rolle's theorem holds for the function f(x)=2x3+ax2+bx in the interval [-1, 1] for the point c=12, then the value of 2a+b is

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a

2

b

1

c

-2

d

-1

answer is B.

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Detailed Solution

f(-1)=f(1)⇒-2+a-b=2+a+b ⇒2b=-4 ⇒b=-2 f1(x)=6x2+2ax+b f1(c)=0 ⇒ f1(12)=0 ⇒64+a-2=0 ⇒ a=2-32=12 2a+b=1-2=-1

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