If the root-mean-square velocity of hydrogen molecule at a given temperature and pressure is 2 km/s, the root-mean-square velocity of oxygen at the same condition (in km/s) is

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2.0

0.5

1.5

1.0

answer is B.

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Detailed Solution

$\begin{aligned} V_{rms} = \sqrt{\frac{3 RT}{M}} \\ \frac{V_{1}}{V_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} \Rightarrow \frac{2}{V_{2}} = \sqrt{\frac{32}{2}} \\ V_{2} = 0.5 km / s \end{aligned}$

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