If the roots of Quadratic equation $a x^{2} + b x + c$ are reciprocal to each other,

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Both A and B

Product of the roots is “1”

$a = c$

Product of the roots is $\frac{" c "}{b}$

answer is D.

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Detailed Solution

$a x^{2} + b x + c L e t t h e r o o t b e α, \frac{1}{α} α + \frac{1}{α} = - \frac{b}{a} α \times \frac{1}{α} = \frac{c}{a} \Rightarrow \frac{c}{a} = 1 \Rightarrow a = c S u m o f t h e r o o t s = \frac{- b}{a} = \frac{- b}{c}$

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