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Q.

If the roots of the equation  ax2+x+b=0 be real, then the roots of the equation x2-4abx+1=0 will be

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a

Real

b

Rational

c

Imaginary

d

Irrational

answer is D.

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Detailed Solution

ax2+x+b=0 has real roots

(1)2-4ab0-4ab1 or 4ab1   ...(i)

Now second equation is x2-4abx+1=0

Therefore D=16ab-4, from (i) D0

Hence roots are imaginary.

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