$\text{ If the roots of the quadratic }$$\text{ equation }{x}^2+px+q=0\text{ are tan }$$30°\text{ and }\tan 15°\text{ , respectively, then }$$\text{ the value of }2+q-p\text{ is }$

$\begin{array}{l}\text{ Given equation is }{x}^2+px+q=0\\ \text{ Sum of roots }=\tan {30}^{°}+\tan {15}^{°}=-\text{p}\\ \text{ Product of roots }=\tan {30}^{°}\cdot \tan {15}^{°}=\text{q}\\ \tan {45}^{°}=\frac{\tan {30}^{°}+\tan {15}^{°}}{1-\tan {30}^{°}\cdot \tan {15}^{°}}=\frac{-p}{1-q}=1\\ \Rightarrow -p=1-q\Rightarrow q-p=1\\ \therefore 2+q-p=3\end{array}$