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Q.

If the roots of x48x3+23x2+kx+12=0  are such that the difference of the two roots is equal to the difference of other two then k=

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a

28

b

30

c

28

d

30

answer is B.

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Detailed Solution

αβ=γδ

α+δ=β+γ=4

α+β+γ+δ=8

2(α+δ)=8

α+δ=4

x48x3+23x2+kx+12=(x2x(α+δ)+αδ)(x2x(β+γ)+βγ)

=(x24x+p1)(x24x+p2)

=x44x3+p2x24x3+16x24p2x+p1x24xp1+p1p2

Coefficient of x223=p2+16+p1

p1+p2=7

Coefficients of xk=4p24p1

=4(p1+p2)

=4(7)

=28

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