If the roots of ${\mathrm{x}}^3 – 9{\mathrm{x}}^2 + \mathrm{kx} + \mathrm{l} = 0$ are in A.P with common difference 2 then (k, l) =

$\begin{array}{l}a-2,a,a+2arerootsof{x}^3-a{x}^2+kx+kx+l=0\\ \therefore a-2+a+a+2=9\\ \Rightarrow 3a=9\Rightarrow a=3\\ \therefore Therootsare1,3,5\\ \therefore K=1\left(3\right)+3\left(5\right)+1\left(5\right)=3+15+5=23\\ l=-\left(1\right)\left(3\right)\left(5\right)=-15\end{array}$