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Q.

If the second ionization potential of helium is 54.4eV, then possible energy states of H+ ion is /are

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a

13.6eV

b

None of these

c

+3.4eV

d

13.6 eV

answer is B.

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Detailed Solution

E1(He+)=1E2(He)=54.4eV

The other energy states can be obtained from E1n2 where n = 1, 2, 3

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