If the shortest wavelength of H atom in Lyman series is ‘x’ , then longest wavelength in Balmer series of He⁺ is

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5x/9

4x/9

9x/5

x/4

answer is D.

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Detailed Solution

The problem asks for the longest wavelength in the Balmer series of the He⁺ ion, given that the shortest wavelength in the Lyman series of the hydrogen atom is 'x'. Let's break this down step-by-step.

The shortest wavelength in the Lyman series corresponds to the transition from $n = 2$ $n$ $=$ $2$ to $n = 1$ $n$ $=$ $1$ in the hydrogen atom. Using the Rydberg formula, the wavelength for any transition in the Lyman series of H is given by: