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Q.

If the side of the equilateral triangle expands at the rate of 2 cm/sec. Then the rate of increase of its area when each side is 10 cm is (in sq. cms)

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answer is 17.

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Detailed Solution

  Let x be length of side and A be area of an equilateral triangleGiven that x=10 ,dxdt=2Now A=area=34x2⇒dAdt=32(x)dxdtdAdt=32×10×2=103

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