If the sides of a triangle are 56 cm, 60 cm, and 52 cm long. Then the area of the triangle will be:

All the sides of a triangle are given so we can find the area of a triangle using Heron’s formula.

Let the sides of the triangle are a = 56 cm, b= 60 cm, c = 52 cm

Semiperimeter (s) $=\raisebox{1ex}{$ (56+60+52)$}\!\left/ \!\raisebox{-1ex}{$2$}\right. = 84 cm$

Now, by using Heron’s formula 

Area of the triangle (A) = $\sqrt{[s (s-a) (s-b) (s-c\left)\right]}$  square units

$$\begin{gathered} A= \sqrt{[84 (84-56) (84-60) (84-52\left)\right]} \\ =\sqrt{[84 (28) (24) (32\left)\right]} \\ = \sqrt{1806336} \\ = 1344 c{m}^2 \end{gathered}$$ 

Thus, the area of the triangle is 1344 cm²