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If the sides of a triangle $Δ A B C$ are 5,7,8 units then area of triangle is

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$10 \sqrt{3}$ sq. units

$20 \sqrt{3}$ sq. units

$15 \sqrt{3}$ sq. units

$5 \sqrt{3}$ sq. units

answer is A.

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Detailed Solution

$s = \frac{5 + 7 + 8}{2} = \frac{20}{2} = 10$

$s - a = 10 - 7 = 3$

$s - b = 10 - 7 = 3$

$s - c = 10 - 8 = 2$

$D = \sqrt{s (s - a) (s - b) (s - c)} = \sqrt{10 \times 5 \times 3 \times 2} = 10 \sqrt{3} s . q u n i t s$

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