If the solubility products of AgCl and AgBr are 1.2 × 10^–10 and 3.5 × 10^–13 respectively, then the relation between the solubilities (denoted by the symbol ‘S’) of these salts can correctly be represented as

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S of is AgBr greater than that of AgCl

S of is AgBr times greater than that of AgCl

S of is AgBr less than that of AgCl

S of is AgBr equal to that of AgCl

answer is A.

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Detailed Solution

K_sp = S₁x S₁

⇒ 1.2 x10^-10 = $s_{1}^{2}$

K_sp = S₂ x S₂

⇒ 3.5 x10^-13 = $s_{2}^{2}$

By observation, S₁ > S₂

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