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If the sound emitted by a point source reaches a particular position with an intensity I, then the change in intransigent level at that position if N such sources are placed together is

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log N

2 log N

10 log N

12 log N

answer is C.

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Detailed Solution

$B_{1} = 10 \log (\frac{I}{I_{0}}) and B_{f} = 10 \log (\frac{NI}{I_{0}}) B_{f} = 10 [\log N + \log \frac{I}{I_{0}}] or B_{f} = 10 \log N + 10 \log B_{i} = 10 \log N + B_{i} B_{f} - B_{i} = 10 \log N$

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