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If the speed of longitudinal waves is equal to 10 times the speed of tranverse wave in a stretched wire of material which has modulus of elasticity E, then the stress in the wire is

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$\frac{E}{100}$

$\frac{E}{10}$

10 E

100 E

answer is C.

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Detailed Solution

$\sqrt{\frac{E}{ρ}} = 10 \sqrt{\frac{T}{μ}}$

$100. \frac{T}{μ} = \frac{E}{ρ} \Rightarrow$

$100. \frac{T}{ρ . a} = \frac{E}{ρ}$

$\frac{T}{a} = \frac{E}{100} [∵ ρ . a = μ]$

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