If the speed of tight is $3.0\times {10}^8{ \mathrm{ms}}^{-1}$, calculate the distance covered by light in 2.00 ns.

$2.00 \mathrm{ns}=2.00\times {10}^{-9} \mathrm{s} \left(1 \mathrm{ns}={10}^{-9} \mathrm{s}\right)$

Distance covered = Speed x Time

$=3.0\times {10}^8{ \mathrm{ms}}^{-1}\times 2.0\times {10}^{-9} \mathrm{s}$

$=6.0\times {10}^{-1} \mathrm{m}=0.6 \mathrm{m}$