Q.

If the standard deviation of 20 observations x1,x2,x3,.....,x20  is 4 and that of another 20 observations y1,y2,y3,.....,y20 is 3. Also  Xi=(xix¯)(yiy¯) where x¯  and  y¯ are means of xi's  and  yi's respectively. If i=120Xi=90 , then the standard deviation of the observations x1y1,x2y2,x3y3,...........,x20y20 is divisible by

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a

2

b

3

c

4

d

5

answer is A, C.

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Detailed Solution

i=120(xix¯)(yiy¯)=90xiyix¯yiy¯xi+x¯y¯1=90xiyi20x¯y¯=90σ2=i=120(xiyi)220(x¯y¯)2=xi220+yi2202xiyi20x¯2y¯2+2x¯y¯=16+9220(90)=16σ=4

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