If the standard electrode potential of Cu2+/Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of Cu2+ (T = 298 K)

E=E0+0.059nlog10⁡Cu2+(n=2)=0.34+0.0592log10⁡10−2=0.281V

If the standard electrode potential of Cu2+/Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of Cu2+ (T = 298 K)

E=E0+0.059nlog10⁡Cu2+(n=2)=0.34+0.0592log10⁡10−2=0.281V

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If the standard electrode potential of Cu²⁺/Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of Cu²⁺ (T = 298 K)

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answer is A.

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Detailed Solution

$\begin{array}{l} E = E^{0} + \frac{0.059}{n} \log_{10} [{Cu}^{2 +}] (n = 2) \\ = 0.34 + \frac{0.059}{2} \log_{10} (10^{- 2}) = 0.281 V \end{array}$

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If the standard electrode potential of Cu2+/Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of Cu2+ (T = 298 K)

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If the standard electrode potential of Cu²⁺/Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of Cu²⁺ (T = 298 K)