Q.

If the standard enthalpy change ΔrHθ for reaction H2(g)+Br2(l)2HBr(g) is 72.8kJ the standard enthalpy of formation ΔfH of HBr(g) in kJ mol 1 is

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a

+36.4

b

+18.2

c

-36.4

d

-18.2

answer is A.

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Detailed Solution

If enthalpy of formation of 2 moles of HBr is 72.8kJ, then for 1 mole it is -36.4 kJ.

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