Q.

 If the standard molar enthalpy of formation of SO2(g) and SO3(g) is – 296.82kJ mol–1 and – 395.72 kJ mol–1 respectively, the heat of reaction in kJ mol–1, for SO2(g) + 1/2 O2(g) → SO3(g), is

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a

+ 98.9

b

– 98.9

c

– 296.82

d

– 395.72

answer is D.

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Detailed Solution

\begin{array}{l} S{O_{2(g)}} + {\rm{ }}\frac{1}{2}{\rm{ }}{O_{2(g)}} \to {\rm{ }}S{O_{3(g)}};{\rm{ }}\Delta H = ?\\\\ \Delta H = [\Delta {H_f}(S{O_3})] - [\Delta {H_f}(S{O_2}) + \frac{1}{2}\Delta {H_f}({O_2})]\\\\ \,\,\,\,\,\,\,\, = - 395.72 - [ - 296.82 + 0] = - 98.9KJ \end{array}

 

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 If the standard molar enthalpy of formation of SO2(g) and SO3(g) is – 296.82kJ mol–1 and – 395.72 kJ mol–1 respectively, the heat of reaction in kJ mol–1, for SO2(g) + 1/2 O2(g) → SO3(g), is