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If the standard molar enthalpy of formation of SO_2(g) and SO_3(g) is – 296.82kJ mol^–1 and – 395.72 kJ mol^–1 respectively, the heat of reaction in kJ mol^–1, for SO_2(g) + 1/2 O_2(g) → SO_3(g), is

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+ 98.9

– 98.9

– 296.82

– 395.72

answer is D.

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Detailed Solution

\begin{array}{l} S{O_{2(g)}} + {\rm{ }}\frac{1}{2}{\rm{ }}{O_{2(g)}} \to {\rm{ }}S{O_{3(g)}};{\rm{ }}\Delta H = ?\\\\ \Delta H = [\Delta {H_f}(S{O_3})] - [\Delta {H_f}(S{O_2}) + \frac{1}{2}\Delta {H_f}({O_2})]\\\\ \,\,\,\,\,\,\,\, = - 395.72 - [ - 296.82 + 0] = - 98.9KJ \end{array}

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