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If the straight line y = 4x + c is a tangent to the ellipse $x^{2} / 8 + y^{2} / 4 = 1$ then c will be equal to

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±4

$\pm \sqrt{(132)}$

±1

±6

answer is D.

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Detailed Solution

$c^{2} = a^{2} m^{2} + b^{2}$

where $a^{2} = 8, b^{2} = 4, m = 4$

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