If the sum of first two terms of infinite G.P is 1 and every term is twice the sum of all the successive terms ,then 

Let the terms of G.P be $a,ar,a{r}^2,a{r}^3\mathrm{...}$

Sum of first two terms $a+ar=1$

$a=2(ar+a{r}^2+a{r}^3+\mathrm{...})$

$\Rightarrow 3a=2(a+ar+a{r}^2+a{r}^3+\mathrm{...})$

$\Rightarrow 3a=\frac{2a}{1-r}$

$\Rightarrow 3-3r=2$

$\Rightarrow r=\frac{1}{3}$

$a+ar=1$

$\Rightarrow a(1+\frac{1}{3})=1$

$\Rightarrow a\left(\frac{4}{3}\right)=1$

$\Rightarrow a=\frac{3}{4}$