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Q.

If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is


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a

     203400

b

     194400

c

     198400

d

     205400 

answer is B.

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Detailed Solution

Given,the sum of LCM and HCF of two numbers is 1260 and LCM is 900 more than their HCF.
Let a and b be two numbers and let x be the LCM and y be the HCF.
Sum of LCM and HCF of two numbers is 1260.
x+y=1260(1) LCM is 900 more than their HCF xy=900(2)  
Add (1) and (2)
x+y+xy=1260+900 2x=2160 x= 2160 2 x=1080 That is, LCM (a,b)=1080  
Subtract (2) from (1)
x+y(xy)=1260900 2y=360 y= 360 2 y=180   That is, HCF (a, b) = 180.
a×b =LCM(a,b)×HCF(a,b) =1080×180 =194400  
Therefore, product of two numbers is 194400.
Hence the correct option is 2.
 
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If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is