Q.

If the sum of odd terms and sum of even terms in (x + a)n are p and q respectively, then 4pq =

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a

(x + a)2n - (x  a)2n

b

(x + a)n + (x  a)n

c

(x + a)2n + (x  a)2n

d

(x + a)n - (x  a)n

answer is C.

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Detailed Solution

P=C0  n (x)n+C2  n (a)n-2 a2+.....q=C1  n (x)n-1 a+C3  n xn-3 a3+......(x+a)n=p+q, (x-a)n=(p-q)(x+a)2n=(p+q)2, (x-a)2n=(p-q)2 4pq=(p+q)2-(p-q)2=(x+a)2n-(x-a)2n

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