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Q.

If the sum of squares of first n natural numbers is given by 1 6 n(n+1)(2n+1) or  1 6 2 n 3 +3 n 2 +n  


Then, what will be the sum of squares of the first 10 natural numbers?


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a

485

b

385

c

956

d

145 

answer is B.

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Detailed Solution

Given data,
The sum of squares of first n natural numbers is given by,
1 6 n(n+1)(2n+1) or  1 6 2 n 3 +3 n 2 +n  
Substitute n=10   in the expression,
1 6 2 n 3 +3 n 2 +n  
Sum of squares of first 10 natural numbers,
S 10 = 1 6 2 10 3 +3 10 2 +10 = 1 6 2000+300+10 = 2310 6 S 10 =385  
Therefore, the sum of squares of the first 10 natural numbers is 385.
Hence, option 2 is correct.
 
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