Q.

 If the sum of the first 20 terms of the series log(72)x+log73x+log74x+.. is 460 , then x is equal to

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a

71/2

b

746/21

c

e2

d

72

answer is D.

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Detailed Solution

The given equation is 

2log7x+3log7x+4log7x+..=460(20 terms )(2+3+4+)log7x=46021×222-1log7x=460

log7x=2x=72

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