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If the sum of the first 2n terms of 2, 5, 8,………… is equal to the sum of the first n terms of 57, 59, 61…… ..... , then n is equal to.

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answer is C.

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Detailed Solution

Given,

$\begin{aligned} \frac{2 n}{2} {2.2 + (2 n - 1) 3} = \frac{n}{2} {2.57 + (n - 1) 2} \\ or 2 (6 n + 1) = 112 + 2 n or 10 n = 110 \end{aligned} ∴ n = 11$

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