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Q.

If the tangents PA  and PB  from a point P  to the circle with centre O  are inclined to each other at an angle of 110° , then POA  is equal to

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a

45°

b

35°

c

50°

d

70°

answer is B.

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Detailed Solution

APB=110°

AOB+APB=180°

AOB=180°110°=70°

POA=POB=702=35°

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