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Q.

If the tangent.to the circle x2+y2=5 at (1,−2) also touches the circle x2+y2−8x+6y+20=0 Then the point of contact is  

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a

(5,2)

b

(−1,0)

c

(1,0)

d

(3,−1)

answer is B.

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Detailed Solution

detailed_solution_thumbnail

Equation of the tangent at  (1,−2) to x2+y2=5 is x−2y−5=0

By  verirification only (3,−1) lies on x−2y−5=0 

 

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