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Q.

If the third term of G.P is 4, then product of first 5 terms.

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a

1024

b

1023

c

1021

d

1022

answer is C.

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Detailed Solution

$Given t_{3} = a r^{2} = 4$

Product of first 5 terms = $(a) (a r) (a r^{2}) (a r^{3}) (a r^{4}) = a^{5} r^{10} = {(a r^{2})}^{5} = 4^{5} = 1024$

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