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Q.

If the transformed equation of a curve is 3X2+XYY27X+Y+7=0 when the axes are translated to the point (1, 2), then the original equation of the curve is 

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a

3x2+xyy2+15x+4y+13=0

b

3x2+xyy215x+4y+13=0

c

3x2+xy+y215x+4y+13=0

d

3x2+xyy2+15x4y+13=0

answer is B.

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Detailed Solution

X= x -1, Y = y-2

The original equation is 3(x1)2+(x1)2+(x1)(y2)(y2)27(x1)+(y2)+7=0

3x2+xyy215x+4y+13=0

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