If the two diagonals of one of its faces are 6i^+6k^ are 4j^+2k^ and of the edges not containing the given diagonals is c→=4j^−8k^ then the volume of a parallelopiped is

∴ Area of the base of the parallelepiped =12|a→×b→|=12(12×3)=18∴ Volume of the parallelepiped =18×203=120

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If the two diagonals of one of its faces are $6 \hat{i} + 6 \hat{k} are 4 \hat{j} + 2 \hat{k}$ and of the edges not containing the given diagonals is $\vec{c} = 4 \hat{j} - 8 \hat{k}$ then the volume of a parallelopiped is

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answer is 120.

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$∴$ Area of the base of the parallelepiped $= \frac{1}{2} | \vec{a} \times \vec{b} |$

$= \frac{1}{2} (12 \times 3) = 18$

$∴$ Volume of the parallelepiped $= 18 \times \frac{20}{3} = 120$

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