Q.

If the two equations x2Kx21=0 and x23Kx+35=0  have a common root, and K > 0 then the value of K is

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a

4

b

2

c

1

d

3

answer is C.

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Detailed Solution

Two equations a1x2+b1x+c1=0,a2x2+b2x+c2=0,wherea1b2a2b10 have common root, if 

(c1a2c2a1)2=(a1b2a2b1)(b1c2b2c1)

(2135)2=(3K+K)(35K63K)

  K2=16

 K= 4

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