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If the uncertainty in velocity of a moving object is 1.0 × 10^–6 m s^–1 and the uncertainty in its position is 58 m, the mass of this object is approximately equal to that of
$(h = 6 .626 \times 10^{- 34} Js)$

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Helium

Deuterium

Lithium

Electron

answer is D.

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Detailed Solution

$∆ x \times m \times ∆ v = \frac{h}{4 π} 58 \times m \times 1.0 \times 10^{- 6} = \frac{6.626 \times 10^{- 34}}{4 \times 3.14} m = 9.091 \times 10^{- 31} kg$

The given mass corresponds to electron.

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