If the unit of length is doubled, unit of time is halved and unit of force is quadrupled, the unit of power would change by the factor

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Detailed Solution

$\begin{array}{l} p = \frac{FL}{T} \\ F^{1} = 4 F, L^{1} = 2 L, T^{1} = \frac{T}{2} \\ P^{1} = \frac{F^{1} L^{1}}{T^{1}} \Rightarrow P^{1} = 16 \frac{FL}{T} \Rightarrow P^{1} = 16 P \end{array}$

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