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Q.

If the unit of power is million erg/minute, the unit of force is 1000 dyne and the unit of length is 5/3 cm then the unit of time is (in second)

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a

1

b

10

c

1/ 100

d

1 /10

answer is C.

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Detailed Solution

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$\begin{array}{l} P = 1 million erg / \min = 10^{6} \times \frac{dyne cm}{60 \sec} \\ P = F \cdot V = {FLT}^{- 1} = \frac{FL}{T} \\ T = \frac{FL}{P} = \frac{10^{3} dyne \times \frac{5}{3} cm}{10^{6} \frac{dyne cm}{60 \sec}} \\ = \frac{10^{3} \times 5}{10^{6} \times 3} \times 60 \sec = \frac{1}{10} \sec \end{array}$

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