If the value of cot = 13 then1 - cos2θ2- sin2θ is ___

cot = 13= 1 2cosec2θ-1 = 1 2cosec2θ-2 -1 + 2=1 2(cosec2θ-1) + 1 Hence, 1 - cos2θ2- sin2θ is 35

If the value of cot = 13 then1 - cos2θ2- sin2θ is ___

cot = 13= 1 2cosec2θ-1 = 1 2cosec2θ-2 -1 + 2=1 2(cosec2θ-1) + 1 Hence, 1 - cos2θ2- sin2θ is 35

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If the value of cot𝝷 = $\frac{1}{\sqrt{3}}$ then $\frac{1 - co s^{2} θ}{2 - si n^{2} θ}$ is ___

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\frac{2}{5}

\frac{4}{5}

\frac{3}{5}

\frac{8}{5}

answer is C.

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Detailed Solution

cot𝝷 =

\frac{1}{\sqrt{3}}

\frac{1}{2 cose c^{2} θ - 1}

\frac{1}{2 cose c^{2} θ - 2 - 1 + 2}

\frac{1}{2 (cose c^{2} θ - 1) + 1}

Hence,

\frac{1 - co s^{2} θ}{2 - si n^{2} θ}

\frac{3}{5}

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