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If the vector $a = 2 i + 3 j + 6 k$ and $b$ are collinear and $|b| = 21$ then $b =$

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$\pm (2 i + 3 j + 6 k)$

$\pm 3 (2 i + 3 j + 6 k)$

$i + j + k$

$\pm 21 (2 i + 3 j + 6 k)$

answer is B.

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Detailed Solution

$b = \times a \Rightarrow |b| = |\times| |a| \Rightarrow 21 = \pm λ (>) \Rightarrow λ = \pm 3 ∴ b = \pm 3 (2 i + 3 j + 6 k)$

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