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Q.

If the vectors 2i^+3j^4k^ and 3i^aj^+bk^ are parallel, find the values of  a and b

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a

a=4,b=5

b

a=92,b=6

c

a=8,b=2

d

a=6,b=92

answer is A.

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Detailed Solution

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Two vectors are parallel if the cross product of them is zero. ie A×B=0

(2i^+3j^4k^)×(3i^aj^+bk^)=0

(3b4a)i^(2b+12)j^+(2a9)k^=0

2b12=0            b=6

3b4a=0

3b=4a.

3(6)=4a

a=9/2,  b=6

Alternatively: 
Two vectors A  and  B  are parallel if

AxBx=AyBy=AzBz

23=3a=4ba=92,   b=6
 

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