If the vectors a¯=2i¯+3j¯+4k¯, b¯=i¯+j¯+5k¯ and c¯ forms a left handed system then c¯=

a¯,b¯,c¯ are in R.H.S ⇒[a¯ b¯ c¯]>0 L.H.S ⇒[a¯ b¯ c¯]<0

If the vectors a¯=2i¯+3j¯+4k¯, b¯=i¯+j¯+5k¯ and c¯ forms a left handed system then c¯=

a¯,b¯,c¯ are in R.H.S ⇒[a¯ b¯ c¯]>0 L.H.S ⇒[a¯ b¯ c¯]<0

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If the vectors $\bar{a} = 2 \bar{i} + 3 \bar{j} + 4 \bar{k}, \bar{b} = \bar{i} + \bar{j} + 5 \bar{k}$ and $\bar{c}$ forms a left handed system then $\bar{c} =$

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$- 11 \bar{i} + 6 \bar{j} + \bar{k}$

$11 \bar{i} - 6 \bar{j} + \bar{k}$

$- 11 \bar{i} + 6 \bar{j} - \bar{k}$

$11 \bar{i} - 6 \bar{j} - \bar{k}$

answer is A, C.

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Detailed Solution

$\bar{a}, \bar{b}, \bar{c}$ are in R.H.S $\Rightarrow [\bar{a} \bar{b} \bar{c}] > 0$
L.H.S $\Rightarrow [\bar{a} \bar{b} \bar{c}] < 0$

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If the vectors a¯=2i¯+3j¯+4k¯, b¯=i¯+j¯+5k¯ and c¯ forms a left handed system then c¯=

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If the vectors $\bar{a} = 2 \bar{i} + 3 \bar{j} + 4 \bar{k}, \bar{b} = \bar{i} + \bar{j} + 5 \bar{k}$ and $\bar{c}$ forms a left handed system then $\bar{c} =$