If the velocity of a rotating body of mass 10 kg is given by v→=2i^+3j^+6k^ and radius r→=i^+2j^+2k^ vectors, then its angular momentum is

L→=r→×p→p→=mv→=20 i^+30 j^+60 k^r→×p→ = i^j^k^122203060 =60i^-20j^-10k^

If the velocity of a rotating body of mass 10 kg is given by v→=2i^+3j^+6k^ and radius r→=i^+2j^+2k^ vectors, then its angular momentum is

L→=r→×p→p→=mv→=20 i^+30 j^+60 k^r→×p→ = i^j^k^122203060 =60i^-20j^-10k^

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If the velocity of a rotating body of mass 10 kg is given by $\vec{v} = 2 \hat{i} + 3 \hat{j} + 6 \hat{k}$ and radius $\vec{r} = \hat{i} + 2 \hat{j} + 2 \hat{k}$ vectors, then its angular momentum is

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$50 \hat{i} + 50 \hat{j} + 100 \hat{k}$

$- 50 \hat{i} + 20 \hat{j} + 10 \hat{k}$

$- 50 \hat{i} + 100 \hat{j} + 50 \hat{k}$

$60 \hat{i} - 20 \hat{j} - 10 \hat{k}$

answer is D.

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Detailed Solution

$\vec{L} = \vec{r} \times \vec{p}$

$\vec{p} = m \vec{v} = 20 \hat{i} + 30 \hat{j} + 60 \hat{k}$

$\vec{r} \times \vec{p} = |\begin{matrix} \hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & 2 \\ 20 & 30 & 60 \end{matrix}| = 60 \hat{i} - 20 \hat{j} - 10 \hat{k}$

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If the velocity of a rotating body of mass 10 kg is given by v→=2i^+3j^+6k^ and radius r→=i^+2j^+2k^ vectors, then its angular momentum is

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If the velocity of a rotating body of mass 10 kg is given by $\vec{v} = 2 \hat{i} + 3 \hat{j} + 6 \hat{k}$ and radius $\vec{r} = \hat{i} + 2 \hat{j} + 2 \hat{k}$ vectors, then its angular momentum is