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Q.

If the velocity of a rotating body of mass 50 kg is given by V=3i^+4j^+5k^ and radius vector r=2i^+3j^+4k^, then its angular momentum is

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a

50i^+50j^+50k^

b

50i^+100j^+50k^

c

50i^+50j^+100k^

d

-50i^+100j^-50k^

answer is D.

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Detailed Solution

Given,

V=3i^+4j^+5k^

r=2i^+3j^+4k^,

We know that angular momentum,

L=r×p=m(r×v)

=50(2i^×(4j^+5k^)+3j^×(3i^+5k^))+4k^×(3i^+4j^))

=50(8k^+10(-j^)+9(-k^)+15(i^)+12j^+16(-i^))

=50(-i^+2j^-k^)=-50i^+100j^-50k^

Hence the correct answer is -50i^+100j^-50k^.

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If the velocity of a rotating body of mass 50 kg is given by V→=3i^+4j^+5k^ and radius vector r→=2i^+3j^+4k^, then its angular momentum is