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Q.

If the velocity of light c, acceleration due to gravity g, and the atmospheric pressure P are taken as the fundamental units, then the unit of mass will be $\dots \dots .. \times 1034 k g$

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answer is 81.

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Detailed Solution

[81] $P = \frac{F}{A} = \frac{m a}{L^{2}} = \frac{m g}{L^{2}} \Rightarrow m = \frac{ρ L^{2}}{g}$
$L^{1} T^{- 1} = 3 \times 10^{8}, L^{1} T^{- 2} = 10 L^{2} T^{- 2} = 9 \times 10^{16} L^{2} \frac{10}{L} = 9 \times 10^{16} L = 9 \times 10^{15} m = \frac{1.01 \times 10^{5} \times 9 \times 10^{15} \times 9 \times 10^{15}}{10} = 81 \times 10^{34} k g$

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If the velocity of light c, acceleration due to gravity g, and the atmospheric pressure P are taken as the fundamental units, then the unit of mass will be …….. ×1034 kg